B^2+3b+14=12

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Solution for B^2+3b+14=12 equation: 



^2+3B+14=12

We move all terms to the left:

^2+3B+14-(12)=0

determiningTheFunctionDomain
3B+14-12+^2=0

We add all the numbers together, and all the variables

3B=0

B=0/3

B=0

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